2x^2+19xy+35y^2=

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Solution for 2x^2+19xy+35y^2= equation: 


Simplifying
2x2 + 19xy + 35y2 = 0

Reorder the terms:
19xy + 2x2 + 35y2 = 0

Solving
19xy + 2x2 + 35y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(2x + 5y)(x + 7y) = 0


Subproblem 1
Set the factor '(2x + 5y)' equal to zero and attempt to solve:

Simplifying
2x + 5y = 0

Solving
2x + 5y = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5y' to each side of the equation.
2x + 5y + -5y = 0 + -5y

Combine like terms: 5y + -5y = 0
2x + 0 = 0 + -5y
2x = 0 + -5y
Remove the zero:
2x = -5y

Divide each side by '2'.
x = -2.5y

Simplifying
x = -2.5y

Subproblem 2
Set the factor '(x + 7y)' equal to zero and attempt to solve:

Simplifying
x + 7y = 0

Solving
x + 7y = 0

Move all terms containing x to the left, all other terms to the right.

Add '-7y' to each side of the equation.
x + 7y + -7y = 0 + -7y

Combine like terms: 7y + -7y = 0
x + 0 = 0 + -7y
x = 0 + -7y
Remove the zero:
x = -7y

Simplifying
x = -7y
Solution
x = {-2.5y, -7y}

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